Given the quadratic function y = 3x-5x-2, when what is the value of X, y = 0, Y0

Let y = 0,
That is, 3x ^ 2-5x-2 = 0
(3X+1)(X-2)=0
X = - 1 / 3 or x = 2,
∵ a = 3 > 0, opening upward,
When x = - 1 / 3 or 2, y = 0,
When X3, Y > 0,
When - 1 / 3

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