Given that the image of quadratic function and a (- 1.4) are vertices and pass through point (2.5), the analytic expression of quadratic function is obtained,

Let y = a (x + 1) ² + 4,
Substituting point B (2,5), we get 5 = 9A + 4, a = - 1;
Therefore, the analytic expression of F (x) is: F (x) = - (x + 1) &# 178; + 4, that is: F (x) = - X & # 178; - 2x + 3

RELATED INFORMATIONS

1. How to draw the image of quadratic function? I see y = 3x ^ 2 confused How to establish? Told me. I will benefit a lot
2. If there is an intersection between the image of the first function y = 5x + m and the image of the second function y = x2 + 3x + 5, then the value range of M is
3. When B is a value, there is one intersection point between the primary function y = 5x + B and the secondary function y = x ^ 2 + 3x + 5, two intersections and no intersection point?
4. Given the quadratic function y = 3x-5x-2, when what is the value of X, y = 0, Y0
5. Quadratic function y = ax ^ 2 + BX + C The distance between the two intersection points of quadratic function y = ax ^ 2 + BX + C and X axis is 4 units. If the image is translated 1.5 units along the symmetric axis, then the image passes through the coordinate origin. If the original image is translated 2 units along the symmetric axis, then the image vertex is on the X axis, and the analytical formula of parabola is obtained
6. It is known that the definition domain of quadratic function y = A & # 178; - 2a-1 is (- ∞, - 1) ∪ (3, + ∞) to find the minimum value of Y
7. Given that the minimum value of quadratic function y = x2 + (2a + 1) x + A2-1 is 0, then the value of a is () A. 34B. -34C. 54D. -54
8. Quadratic function y = a (x-1) &# B has the minimum value - 1, what is a + B The quadratic function y = a (x-1) &# 178; + B has a minimum value of - 1, what is a + B
9. The minimum value of quadratic function y = 15 (x-1) &# 178; is
10. It is known that the quadratic function y = x & # 178; + (2k-1) x + K & # 178; - 1 of X, if the sum of two squares of the quadratic equation x & # 178; + (2k-1) x + K & # 178; - 1 = 0 of X is 9, find the value of K and the vertex coordinates of the parabola, and find the correct vertex coordinates!
11. The vertex (- 2,1) of quadratic function passes through the point (2,1), and the analytic expression of quadratic function is obtained
12. A formula for finding the vertex of quadratic function
13. What is the vertex formula of quadratic function? Vertex formula, not vertex formula The vertex formula is y = a (X-H) ^ 2 + K. I know, but I don't know how to match it. I need a formula
14. Which formula is used to find the analytic formula of the known vertex coordinates of quadratic function?
15. Through the point (- 3,2), the vertex is (- 2,3) to find the quadratic function analytic formula
16. The vertex coordinates of quadratic function are known,
17. Analytic expression of quadratic function determined by vertex coordinates I have learned the analytic formula of quadratic function to determine the vertex coordinates, for example, y = 2 (x-1) + 2, and the vertex coordinates are (1,2). Can we find the vertex coordinates of the analytic formula of quadratic function y = AX2 + BX + C (1.2) on the other hand It's too much trouble for the second floor on the premise that a is the fixed value
18. Know the analytic expression of quadratic function, how to find vertex coordinates?
19. If the inverse function image of y = (A-X) / (x-a-1) is centrosymmetric with respect to the point (- 1,4), then the value of a is? The answer is that a is 3 What should we do
20. The inverse function of y = LNX and the inverse function image of y = ln (1 / x) are symmetric with respect to