Given that the minimum value of quadratic function y = x2 + (2a + 1) x + A2-1 is 0, then the value of a is () A. 34B. -34C. 54D. -54

∵ a = 1, B = 2A + 1, C = A2-1, ∵ 4ac − b24a = 4 (A2 − 1) − (2a + 1) 24 = − 4A − 54 = 0, the solution is: a = - 54

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