It is known that the image of the function f (x) defined on R is symmetric with respect to the point (- 3 / 4,0) and satisfies f (x) = - f (x + 3 / 2). F (- 1) = 1. F (o) = - 2, Then the value of F (1) + F (2) + F (3) +... + F (2008) is () A.-2 B.-1 C.0 D.1
F (- 1) = f (- 1 + 3) = f (2), f (0) = f (0 + 3) = f (3), because about - 3 / 4 symmetry, f (- 1) = f (- 1 / 2) = f (- 1 / 2 + 2 / 3) = f (1), f (1) + F (2) + F (3) = 0, f (1 + 3) = f (4), f (2 + 3) = f (5), f (3 + 3) = f (6) ,2008/3=669…… So f (1) + F (2) + F (3) +... + F (2008) = f (1) = f (- 1) = 1
RELATED INFORMATIONS
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- 2. The image of the function FX defined on R is symmetric with respect to the point a (a, b) B (C, b), and the period of the function is calculated
- 3. As shown in the figure, the image of the first-order function y equal to minus 2x plus B and the image of the second-order function y equal to minus xsquare plus 3x plus C pass through the origin (1) If the line y = KX + m and the line y = negative 2x + B are parallel to the Y axis and intersect at point a and pass through the vertex P of the parabola to find the expression of the line y = KX + m, and (3) find the area of the triangle apo
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- 7. It is known that the image of the first-order function y = 1 / 2 + 4 and the x-axis and y-axis are not called points a and B. the edge AC of the trapezoidal aobc is 5. The coordinate of point C is calculated There seem to be three solutions
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- 11. It is known that the image of the function f (x) defined on R is symmetric with respect to the point (- 3 / 4,0), satisfying f (x) = - f (x + 3 / 2), f (- 1) = 1, f (0) = - 2 Then the value of F (1) + F (2) +... + F (2008) is Please indicate the process
- 12. Given that the image of the function f (x) defined on R is symmetric with respect to the point (- 3 / 4,0) and satisfies f (x) = - f (x + 3 / 2). F (- 1) = 1. F (o) = - 2, then the value of f (1) + F (2) + F (3) +... + F (2008) is () A.-2 B.-1 C.0 D.1
- 13. It is known that the quadratic function y = x square - (m square + 4) x-2m square-12 1. Verification: no matter what real number m takes, the parabola passes through a certain point, and the coordinates of the fixed point are obtained
- 14. The vertex coordinates of the image of quadratic function y = x & # 178; + 1 are
- 15. What is the vertex coordinate of quadratic function y = (x-1) - 2?
- 16. Given that the vertex coordinates of the quadratic function y = (a + 2) x & # 178; + A & # 178; - 1 are (0,3), then a=_____
- 17. It is known that the quadratic function y = x & # 178; + (2k-1) x + K & # 178; - 1 of X, if the sum of two squares of the quadratic equation x & # 178; + (2k-1) x + K & # 178; - 1 = 0 of X is 9, find the value of K and the vertex coordinates of the parabola, and find the correct vertex coordinates!
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- 20. Given that the minimum value of quadratic function y = x2 + (2a + 1) x + A2-1 is 0, then the value of a is () A. 34B. -34C. 54D. -54