If the point a (1, m) is known to be on the image of a linear function y = 3x-2, then M=

That is, M = 3 × 1-2
m=1

RELATED INFORMATIONS

1. It is known that the image of the first-order function is parallel to the image of the positive scale function y = - 2 / 3x and passes through the point m (0,4) If the points (- 8, m) and (n, 5) are on the image of a linear function, try to find the values of M and n
2. It is known that the image of the first-order function is parallel to the image of the positive scale function y = - 2 / 3x and passes through the point m (0,4). Try to find the expression of the first-order function
3. When we know that the image of the first-order function is parallel to the positive scale function y = - 2 / 3x, and the value is in what range through the point m (0,4) X When x is in what range, the value of this linear function is a positive number
4. If the image of a linear function y = MX - (4m-4) passes through the origin, then the value of M is?
5. When m_ When y = MX + m-2, the image passes through the origin
6. If we know that the graph of the first-order function y = MX + 4M-2 passes through the origin, then M is equal to the graph of the first-order function y = MX + 4M-2 It is known that if the graph of a linear function y = MX + 4M-2 passes through the origin, then M is equal to what, and when m = 1 / 3, which quadrants does the image pass through?
7. Given that the image of function y = MX + 4m-3 passes through the origin, the value of M is obtained
8. It is known that f (x) = loga 1-mx / X-1 (a > 0, a ≠ 1, m ≠ 1) is an odd function g(x)=f(x)+loga[(x-1)(ax+1)] 1. Find M 2. Find the definition field of function g (x)
9. Who can help me to review unit 1 ~ 3 of Volume 1 (PEP) of primary school mathematics grade 6
10. There are both chickens and rabbits in the chicken cage. There are 12 counting legs, 4 heads, how many chickens? How many rabbits?
11. Given that the image of the function y = (m-2) x square - 3x + m square + 2m-8 of Y with respect to x passes through the origin, the analytic expression of the function is obtained
12. It is known that the image of the first-order function y = 1 / 2 + 4 and the x-axis and y-axis are not called points a and B. the edge AC of the trapezoidal aobc is 5. The coordinate of point C is calculated There seem to be three solutions
13. It is known that the image of the first-order function y = - 12x + 4 intersects with the x-axis and y-axis at points a and B respectively. The edge AC of the trapezoid aobc is 5. (1) find the coordinates of point C; (2) if points a and C are on the image of the first-order function y = KX + B (K and B are constants, and K < 0), find the analytic expression of the first-order function
14. Given that the image of the first-order function y = & frac12; X + 4 intersects the x-axis and y-axis at points a and B respectively, and the edge AC of the trapezoid aobc (o is the origin) is 5, the coordinates of point C are obtained Point a intersects on the X axis, and point B intersects on the Y axis,
15. It is known that the image of the first-order function y = - 1 / 2x + 4 intersects with the x-axis and y-axis respectively at a, B, and the edge AC = 5 of the trapezoid aobc (o is the origin) (1) Find the coordinate (2) of point C if points a and C are in the linear function y = KX + B (k, B are constants, and K
16. As shown in the figure, the image of the first-order function y equal to minus 2x plus B and the image of the second-order function y equal to minus xsquare plus 3x plus C pass through the origin (1) If the line y = KX + m and the line y = negative 2x + B are parallel to the Y axis and intersect at point a and pass through the vertex P of the parabola to find the expression of the line y = KX + m, and (3) find the area of the triangle apo
17. The image of the function FX defined on R is symmetric with respect to the point a (a, b) B (C, b), and the period of the function is calculated
18. If the domain of F (x) is symmetric about the origin, then f (x) times f (- x) is an even function How to prove it
19. It is known that the image of the function f (x) defined on R is symmetric with respect to the point (- 3 / 4,0) and satisfies f (x) = - f (x + 3 / 2). F (- 1) = 1. F (o) = - 2, Then the value of F (1) + F (2) + F (3) +... + F (2008) is () A.-2 B.-1 C.0 D.1
20. It is known that the image of the function f (x) defined on R is symmetric with respect to the point (- 3 / 4,0), satisfying f (x) = - f (x + 3 / 2), f (- 1) = 1, f (0) = - 2 Then the value of F (1) + F (2) +... + F (2008) is Please indicate the process