It is known that f (x) = loga 1-mx / X-1 (a > 0, a ≠ 1, m ≠ 1) is an odd function g(x)=f(x)+loga[(x-1)(ax+1)] 1. Find M 2. Find the definition field of function g (x)
1) F (x) domain 1-mx / (x-1) = [(1-m) X-1] / (x-1) > 0, the two endpoints of the solution set are 1,1 / (1-m) respectively
Because the definition domain of odd function is symmetric, the two endpoints of solution set are symmetric, that is, 1 / (1-m) = - 1
m=2
2) F (x) domain-1
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