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As shown in the figure, in RT △ AOB, the circle AB with radius OA intersects at point C. If Ao = 5, OB = 12, the length of BC is obtained
Through point E, make OE ⊥ AC at point E, ∵ AOB = 90 °, Ao = 5, OB = 12, ∧ AB = 13, ∧ EO × AB = Ao × Bo, ∧ EO = Ao × boab = 5 × 1213 = 6013, in RT △ AEO, AE = AO2 − EO2 = 2513, ∧ AC = 2513 × 2 = 5013, ∧ BC = 13-5013 = 11913
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