As shown in the figure, it is known that point O is a point on the hypotenuse of RT △ ABC, with point o as the center and OA length as the radius, the center O and BC are tangent to point E As shown in the figure, we know that the point O is a point on the hypotenuse AC of ABC of RT triangle. With the point o as the center and the OA length as the radius, the center O and BC are tangent to point E and intersect with AC at point D, connecting AE. (1) proof: AE bisection angle CAC (2) explore the quantitative relationship between angle 1 and angle C in the figure Just ask the second question, the first question I know

As shown in the figure, it is known that point O is a point on the hypotenuse of RT △ ABC, with point o as the center and OA length as the radius, the center O and BC are tangent to point E As shown in the figure, we know that the point O is a point on the hypotenuse AC of ABC of RT triangle. With the point o as the center and the OA length as the radius, the center O and BC are tangent to point E and intersect with AC at point D, connecting AE. (1) proof: AE bisection angle CAC (2) explore the quantitative relationship between angle 1 and angle C in the figure Just ask the second question, the first question I know

2 ∠ 1 + ∠ C = 90 °, Tanc = root 3 / 3 ∵ ∠ EOC is the outer angle of △ AOE, ∵ 1 + ∠ AEO = ∠ EOC, ∵ 1 = ∠ AEO, ∵ OEC = 90 ° and ∵ 2 ∠ 1 + ∠ C = 90 ° when AE = CE, ∵ 1 = ∠ C, ∵ 2 ∠ 1 + ∠ C = 90 °
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