As shown in the figure, in O, the chord AB = AC = 10, the chord ad intersects BC with E, AE = 4, and the length of ad is calculated

Because chord AB = chord AC, arc AB = arc AC, so ﹥ BCA = ﹥ DCA. In △ ace and △ ADC, ﹥ ace = ﹥ ADC ﹥ CAE = ﹥ DAC, so AC / ad = AE / AC, so ad = AC & ﹥ 178 / / AE = 100 / 4 = 25

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1. As shown in the figure, AB and AC are the chords of ⊙ o, ad ⊥ BC at D, intersection of ⊙ o at F, AE and diameter of ⊙ O. what is the relationship between the two chords be and the size of CF? Explain the reason
2. It is known that: as shown in the figure, AB is the diameter of ⊙ o, AC is the chord, CD ⊥ AB at D. if AE = AC, be intersects ⊙ o at point F, CF and de are connected
3. As shown in the figure, AB and AC are the chords of ⊙ o, ad ⊥ BC at D, intersection of ⊙ o at F, AE and diameter of ⊙ O. what is the relationship between the two chords be and the size of CF? Explain the reason
4. If ad ^ 2 = AE * AC, CD = CB
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