In graph o, the strings AB and CD intersect at E. if arc ad = arc AC, we prove that AC squared = AE multiplied by ab

In graph o, the strings AB and CD intersect at E. if arc ad = arc AC, we prove that AC squared = AE multiplied by ab

Because arc ad = AC
Therefore, the circumference angle ∠ CDA = ∠ DCA, and ∠ ADC and ∠ ABC face the same arc, so they are equal
Therefore, DCA = ABC and cab is the common angle of △ ABC and △ ace
So the two triangles are similar, so there is: AC / AE = AB / AC
So we have AC ^ 2 = AE * ab

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