If one root of the equation MX & # 178; - 2x + 1 = 0 is in the interval (0,1) and the other root is in the interval (1,2), find the value range of the real number M,
Both are positive roots, so the sum of the two is 2 / M > 0, so m > 0
The opening of function f (x) = MX ^ 2-2x + 1 is upward, according to the interval (0,1) and (1,2) where the two roots are located
yes:
F (0) > 0, i.e. 1 > 0
f(1)3/4
The range of M is 3 / 4,1
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