In △ ABC, ab = AC, D is the midpoint of BC, e and F are on AB and AC respectively, and △ DEF is an equilateral triangle

In △ ABC, ab = AC, D is the midpoint of BC, e and F are on AB and AC respectively, and △ DEF is an equilateral triangle

It is proved that DME is equal to dnf by making high DM and DN on AB AC through D point