As shown in the figure, △ ABC is a right triangle, ∠ ACB = 90, ad is the bisector of ∠ BAC, de ⊥ AB, BC = 8, CD = 3, the length of 1.be, 2. The area of △ ABC

The first thing to remember is the theorem that the distance from a point on the bisector of an angle to both ends of the angle is equal
Because ad is the angular bisector of ∠ BAC, and CD = 3
So de = CD = 3,
Because BC = 8, CD = 3
So BD = bc-cd = 5
Because de ⊥ ab
So we can get be = 4 by Pythagorean theorem

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