As shown in the figure, O is any point in the triangle ABC, connecting Ao, Bo and Co
OA+OB
RELATED INFORMATIONS
- 1. As shown in the figure, point O is a point outside △ ABC. Take a ', B', C 'on the ray OA, ob, OC respectively, so that oa'oa = ob'ob = oc'oc = 3. Connect a'B', b'c ', c'a', and whether the obtained △ a'b'c 'is similar to △ ABC? Prove your conclusion
- 2. Given that O is the outer center of △ ABC, e is the inner point of triangle, and OE = OA + ob + OC, it is proved that AE is perpendicular to BC
- 3. In the triangle ABC, if AA CC + BC = BB, then a =?
- 4. Three sides ABC of triangle, find aa-bb-cc-2ab < 0
- 5. The triangle ABC must satisfy π / 3
- 6. Three sides a, B, C of triangle ABC satisfy AA + BB + CC + 338 = 10A + 24B + 26c, and the area of triangle ABC is calculated
- 7. AAA + BBB + CCC = CBBC question; a =? B =? C =?
- 8. AAA+BBB+CCC=CBBC What does a stand for? What does B stand for
- 9. AAA+BBB-CCC=?DDD A
- 10. Note that the lengths of the three sides of the triangle ABC are a, B, C. simplify the algebraic formula ia-b-ci + ia-b + CI + Ia + b-ci
- 11. Point O is any point in the triangle ABC, connecting Ao, Bo and Co. proof: ab + AC > ob + OC AB + BC + AC > OA + ob + OC
- 12. Take any point O in the triangle ABC, connect Ao, Bo, CO respectively, and extend the opposite edge to a ', B', C '. Prove: OA' / AA '+ ob' / BB '+ OC' / CC '= 1
- 13. As shown in the figure, in the triangle ABC, the angle BAC is equal to 90 degrees, ad is perpendicular to BC, and BD square = BD times BC
- 14. As shown in the figure, in the triangle ABC, CD is the height on the side of AB, and the square of CD = ad * BD. try to explain that the triangle ABC is a right triangle
- 15. In the triangle ABC, if the angle a = 120 degrees, ab = 4, AC = 2, then SINB =?
- 16. In the triangle ABC, the angle a = 120 °, ab = 4, AC = 2, then the value of SINB is () Originally there was no picture
- 17. In △ ABC, ab = AC = 10, BC = 16, find the value of tanb
- 18. In △ ABC, ab = AC = 10, BC = 16, find the value of tanb
- 19. As shown in the figure, in △ ABC, ab = AC, D, e are two points on the straight line BC, and ab & # 178; = DB × CE, if ∠ BAC = 40 °, calculate the degree of ∠ DAE
- 20. As shown in the figure, in △ ABC, D and E are on the straight line BC. (1) if AB = BC = AC = CE = BD, calculate the degree of ∠ EAC; (2) if AB = AC = CE = BD, ∠ DAE = 100 °, calculate the degree of ∠ EAC