In the triangle ABC, if AA CC + BC = BB, then a =?

a²-c²+bc=b²
b²+c²-a²=bc
cosA=(b²+c²-a²)/2bc=1/2
A = 60 degrees

RELATED INFORMATIONS

1. Three sides ABC of triangle, find aa-bb-cc-2ab < 0
2. The triangle ABC must satisfy π / 3
3. Three sides a, B, C of triangle ABC satisfy AA + BB + CC + 338 = 10A + 24B + 26c, and the area of triangle ABC is calculated
4. AAA + BBB + CCC = CBBC question; a =? B =? C =?
5. AAA+BBB+CCC=CBBC What does a stand for? What does B stand for
6. AAA+BBB-CCC=?DDD A
7. Note that the lengths of the three sides of the triangle ABC are a, B, C. simplify the algebraic formula ia-b-ci + ia-b + CI + Ia + b-ci
8. If a, B and C are three sides of △ ABC, the result of simplifying | a-b-c | + | b-c-a | + | C-A-B |, is () A. -a-b-cB. a+b+cC. a+b-cD. a-b+c
9. In △ ABC, Bi bisection ∠ ABC, CI bisection ∠ ACB, be, CE are bisection lines of external angle, if ∠ a = 50 °, then ∠ I =? ° ∠ Ube =? ±
10. ）As shown in the figure, it is known that ∠ ABC = 60 °, ACB = 50 °, Bi bisection ∠ ABC, CI bisection ∠ ACB, Bi and CI intersection at I, passing through point I as De, (1) calculate the degree of ∠ BIC (2) Guess the quantitative relationship among BD, CE and De, and explain the reason
11. Given that O is the outer center of △ ABC, e is the inner point of triangle, and OE = OA + ob + OC, it is proved that AE is perpendicular to BC
12. As shown in the figure, point O is a point outside △ ABC. Take a ', B', C 'on the ray OA, ob, OC respectively, so that oa'oa = ob'ob = oc'oc = 3. Connect a'B', b'c ', c'a', and whether the obtained △ a'b'c 'is similar to △ ABC? Prove your conclusion
13. As shown in the figure, O is any point in the triangle ABC, connecting Ao, Bo and Co
14. Point O is any point in the triangle ABC, connecting Ao, Bo and Co. proof: ab + AC > ob + OC AB + BC + AC > OA + ob + OC
15. Take any point O in the triangle ABC, connect Ao, Bo, CO respectively, and extend the opposite edge to a ', B', C '. Prove: OA' / AA '+ ob' / BB '+ OC' / CC '= 1
16. As shown in the figure, in the triangle ABC, the angle BAC is equal to 90 degrees, ad is perpendicular to BC, and BD square = BD times BC
17. As shown in the figure, in the triangle ABC, CD is the height on the side of AB, and the square of CD = ad * BD. try to explain that the triangle ABC is a right triangle
18. In the triangle ABC, if the angle a = 120 degrees, ab = 4, AC = 2, then SINB =?
19. In the triangle ABC, the angle a = 120 °, ab = 4, AC = 2, then the value of SINB is () Originally there was no picture
20. In △ ABC, ab = AC = 10, BC = 16, find the value of tanb