AAA + BBB + CCC = CBBC question; a =? B =? C =?

C stands for 1
B stands for 2
A stands for 8
888+222+111＝1221

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1. AAA+BBB+CCC=CBBC What does a stand for? What does B stand for
2. AAA+BBB-CCC=?DDD A
3. Note that the lengths of the three sides of the triangle ABC are a, B, C. simplify the algebraic formula ia-b-ci + ia-b + CI + Ia + b-ci
4. If a, B and C are three sides of △ ABC, the result of simplifying | a-b-c | + | b-c-a | + | C-A-B |, is () A. -a-b-cB. a+b+cC. a+b-cD. a-b+c
5. In △ ABC, Bi bisection ∠ ABC, CI bisection ∠ ACB, be, CE are bisection lines of external angle, if ∠ a = 50 °, then ∠ I =? ° ∠ Ube =? ±
6. ）As shown in the figure, it is known that ∠ ABC = 60 °, ACB = 50 °, Bi bisection ∠ ABC, CI bisection ∠ ACB, Bi and CI intersection at I, passing through point I as De, (1) calculate the degree of ∠ BIC (2) Guess the quantitative relationship among BD, CE and De, and explain the reason
7. In △ ABC, ad bisects ∠ BAC, intersects BC with D, EF ‖ ad, intersects AC with E, intersects the extension of BA with F. it is proved that △ AEF is an isosceles triangle
8. As shown in the figure, in △ ABC, e is a point on the edge of BC, EF is perpendicular to BC, intersects BA at D, intersects the extension line of Ca at F, if ad = AF, is △ ABC an isosceles triangle
9. The inscribed circle O of the right triangle ABC, the hypotenuse AB at point D, the tangent BC at point F, and the intersection AC of the extension line of Bo at point E
10. As shown in the figure, the inscribed circle O of RT △ ABC cuts the hypotenuse AB to D, cuts BC to F, and the extension line AC of Bo intersects at point E Prove Bo * BC = BD * be
11. Three sides a, B, C of triangle ABC satisfy AA + BB + CC + 338 = 10A + 24B + 26c, and the area of triangle ABC is calculated
12. The triangle ABC must satisfy π / 3
13. Three sides ABC of triangle, find aa-bb-cc-2ab < 0
14. In the triangle ABC, if AA CC + BC = BB, then a =?
15. Given that O is the outer center of △ ABC, e is the inner point of triangle, and OE = OA + ob + OC, it is proved that AE is perpendicular to BC
16. As shown in the figure, point O is a point outside △ ABC. Take a ', B', C 'on the ray OA, ob, OC respectively, so that oa'oa = ob'ob = oc'oc = 3. Connect a'B', b'c ', c'a', and whether the obtained △ a'b'c 'is similar to △ ABC? Prove your conclusion
17. As shown in the figure, O is any point in the triangle ABC, connecting Ao, Bo and Co
18. Point O is any point in the triangle ABC, connecting Ao, Bo and Co. proof: ab + AC > ob + OC AB + BC + AC > OA + ob + OC
19. Take any point O in the triangle ABC, connect Ao, Bo, CO respectively, and extend the opposite edge to a ', B', C '. Prove: OA' / AA '+ ob' / BB '+ OC' / CC '= 1
20. As shown in the figure, in the triangle ABC, the angle BAC is equal to 90 degrees, ad is perpendicular to BC, and BD square = BD times BC