As shown in the figure, the inscribed circle O of RT △ ABC cuts the hypotenuse AB to D, cuts BC to F, and the extension line AC of Bo intersects at point E Prove Bo * BC = BD * be

As shown in the figure, the inscribed circle O of RT △ ABC cuts the hypotenuse AB to D, cuts BC to F, and the extension line AC of Bo intersects at point E Prove Bo * BC = BD * be

prove:
Connect OD, then OD ⊥ ab
∴∠BDO=∠C
∵ o is the center of the inscribed circle of △ ABC
∴∠CBE=∠OBD
∴△BCE∽△BDO
∴BE/BO=BC/BD
∴BO*BC=BD*BE