In the regular triangular prism abc-a1b1c1, ab = 2, Aa1 = 1, find the distance from point a to plane a1bc

In the regular triangular prism abc-a1b1c1, ab = 2, Aa1 = 1, find the distance from point a to plane a1bc

Using equal product
∵VA-A1BC=VA1-ABC
∴(1/3)S△A1BC·hA=(1/3)S△ABC·AA1
∴hA=S△ABC·AA1/S△A1BC=√3/2