Verification: A2 + B2 + 1 ≥ AB + A + B

It is proved that: ∵ A2 + B2 ≥ 2Ab, A2 + 1 ≥ 2a, B2 + 1 ≥ 2B, adding the above three formulas together, 2 (A2 + B2 + 1) ≥ 2 (AB + A + b) ∵ A2 + B2 + 1 ≥ AB + A + B

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