If a and B are the two roots of the quadratic equation x ^ 2 + (M + 2) x + 1 = 0 with respect to x, then what is the value of (1 + Ma + A ^ 2) (1 + MB + B ^ 2)
Weida theorem
ab=1
And x = a
Then a & # 178; + a (M + 2) + 1 = 0
a²+am+2a+1=0
1+ma+a²=-2a
Similarly, 1 + MB + B & # 178; = - 2b
So the original formula = (- 2A) (- 2b)
=4ab
=4
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