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Connect two fixed value resistors in series to both ends of the power supply with voltage of u, the power consumed by R1 is P1, and the power consumed by R2 is 3P1 A. The ratio of voltage between R1 and R2 in series is 3:1b. The power consumed by R1 in parallel is 16p1c. The ratio of current through R1 and R2 in parallel is 1:3d. The total power consumed by two resistors in parallel is 163p1
(1) When R1 and R2 are connected in series, the current through the two resistors is equal, ∵ P = I2R, P2 = 3P1, ∵ R2 = 3R1, ∵ u = IR, ∵ U1: U2 = R1: R2 = 1:3; if the current in the circuit is I = ur1 + R2 = ur1 + 3R1 = u4r1, then P1 = i2r1 = (u4r1) 2r1 = u216r1. (2) when R1 and R2 are connected in parallel at both ends of the same power supply, the voltage at both ends of the two resistors is equal to u, and the power consumed by R1 is P1 ′ = u2r1 = 16p1; ∵ I = ur, ∵ on The ratio of current passing through R1 and R2 is I1 ′: I2 ′ = R2: R1 = 3:1; the total power consumed by the circuit is p ′ = u2r1 + u2r2 = u2r1 + u23r1 = 43 × 16p1 = 643p1
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