It is known that, as shown in the figure, in the triangle, AB equals AC equals 20cm, angle ABC equals angle ACB equals 15 degrees, and the area of triangle angle ABC is calculated Sorry, there is no picture. Let me describe it If this is the graph of the problem, the top point is a, the left side is B, and the right side is C. It is known that the left and right sides are equal to 20cm, and the two bottom sides are 15 ° to find the area of the triangle

It is known that, as shown in the figure, in the triangle, AB equals AC equals 20cm, angle ABC equals angle ACB equals 15 degrees, and the area of triangle angle ABC is calculated Sorry, there is no picture. Let me describe it If this is the graph of the problem, the top point is a, the left side is B, and the right side is C. It is known that the left and right sides are equal to 20cm, and the two bottom sides are 15 ° to find the area of the triangle

Known, as shown in the figure, in the triangle, AB equal to AC equal to 20cm, angle ABC equal to angle ACB equal to 15 degrees, find the triangle angle ABC area
The distance from point C to edge AB = 10, that is, the height of edge AB = 10
Triangle angle ABC area = bottom x height / 2 = 20X10 / 2 = 100