In the triangle ABC, angle c = 90, ab = 10, AC = 6, find BC and area

Angle c = 90 degrees, ab = 10, AC = 6, BC = √ AB-AC = √ 10-6 = 8, s = 1 / 2, BC * AC = 1 / 2 * 8 * 6 = 24 and 1 / 2 * AB * H = s = 24 (H is the height of AB side) H = 24 * 2 / 10 = 24 / 5

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