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The sum of squares of four numbers is 94. The product of the first number and the fourth number is 18 less than the product of the second number and the third number
Let four numbers be a-3d, A-D, a + D, a + 3D. According to the meaning of the title, we can get (a-3d) 2 + (A-D) 2 + (a + D) 2 + (a + 3D) 2 = 94, so there are 2A2 + 10d2 = 47. ① and (a-3d) (a + 3D) = (A-D) (a + D) - 18, we can get 8d2 = 18, and the solution is d = ± 32. Substituting ① to get a = ± 72, so the four numbers are 8
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