As shown in the figure, the side length of equilateral △ ABC is 6, ad is the middle line on BC side, M is the moving point on ad, e is a point on AC side. If AE = 2, the minimum value of EM + cm is () A. 27B. 4C. 37D. 1+27

Connect be and ad at the point g. ∵ △ ABC is an equilateral triangle, ad is the middle line on the edge of BC, ∵ ad ⊥ BC, ∵ ad is the vertical bisector of BC, ∵ the corresponding point of point c about AD is point B, ∵ be is the minimum value of EM + cm. ∵ point G is the calculated point, that is, point G coincides with point m, take the midpoint F of CE, and connect DF. ∵ equilateral ∵ ABC's side length is 6, AE = 2, ∵ CE = ac-ae = 6-2 = 4, ∵ CF = EF = AE = 2, and In the right angle △ BDM, BD = 12bc = 3, DM = 12ad = 332, BM = BD2 + DM2 = 327, be = 43 × 327 = 27. The minimum value of ∫ EM + cm = be ∫ EM + cm is 27. So a

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1. As shown in the figure: the side length of equilateral △ ABC is 5, ad is the middle line on BC side, M is the moving point on ad, e is a point on AC side. If AE = 2, the minimum value of EM + cm is________ The title says that the length of the side is 5. I can't find it on the Internet. I want the mid-term exam tomorrow
2. As shown in the figure, the side length of equilateral △ ABC is 12, ad is the middle line on BC side, M is the moving point on ad, e is a point on AC side, if AE = 4, the minimum value of EM + cm is______ ．
3. As shown in the figure, in △ ABC, ab = AC, be = AE, the perimeter of △ BCE is 12, BC = 5, find the length of ab
4. As shown in the figure, ad and AE are the height and middle line of the triangle ABC respectively, and ab = 8, AC = 5. What is the perimeter of the triangle Abe over the triangle ace? What is the relationship between the area of triangle Abe and triangle ace?
5. As shown in the figure, △ ABC, ab = AC, D is the moving point on AB, DF ⊥ BC is at point F, and Ca extension line is at point E, (1) (2) when point D is on the extension line of Ba, other conditions remain unchanged. (1) is the conclusion still valid? Please give reasons
6. As shown in the figure, abad = BCDE = ACAE, verification: △ abd ∽ ace
7. As shown in the figure, ab ⊥ AC, ab = AC, ad ⊥ AE, ad = AE
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9. As shown in the figure, abad = BCDE = ACAE, verification: △ abd ∽ ace
10. As shown in the figure, abad = BCDE = ACAE, verification: △ abd ∽ ace
11. Let the area of the quadrilateral ABCD be one, divide the edge ad into three equal parts, the dividing point is E.F, let AE = EF = FD, and divide BC into three equal parts, the dividing point is H.G, so that BH = Hg = GC Connecting EF and GH to prove s quadrilateral efgh = 1 / 3
12. As shown in the figure, the side length of equilateral triangle ABC is 6, ad is the middle line on the side of BC, M is the moving point on ad, e is the point on AC, if AE = 2, then the minimum value of EM + cm is?
13. In triangle ABC, D is the point on AC, passing through point D as de parallel to CB, intersecting point AB at point E, and the area ratio of triangle ade to triangle ace is 1:16
14. As shown in the figure, in RT △ ABC, ∠ B = 90 °, ab = 1, BC = 12, take point C as the center, CB as the radius of arc intersection Ca at point D; take point a as the center, ad as the radius of arc intersection AB at point E. (1) find the length of AE; (2) take points a and E as the center, AB length as the radius of arc, two arcs intersect at point F (F and C are on both sides of AB), connect AF and EF, let the circle where EF intersects de at point G, connect AG, try to guess Think about the size of EAG and explain the reason
15. In the triangle ABC, CD is high, e is the midpoint of CD, the extension line of AE intersects CB at point F, AE = CE and AF is vertical to CB. If EF = 1, then AE
16. Known: as shown in the figure, take two right angle sides AB and BC of RT △ ABC as sides to make equilateral △ Abe and equilateral △ BCF, connect EF and EC, please explain EF = EC
17. Taking the two right sides AB and BC of the right triangle ABC as one side, make the equilateral triangle △ Abe and equilateral △ BCF outward respectively, connecting EF and EC. Try to explain: (1) EF = EC; (2) EB ⊥ CF
18. Taking the two right sides AB and BC of the right triangle ABC as one side, make the equilateral triangle △ Abe and equilateral △ BCF outward respectively, connecting EF and EC. Try to explain: (1) EF = EC; (2) EB ⊥ CF
19. As shown in the figure, △ Abe and △ ACD are respectively formed by △ ABC folding along AB and AC sides. If ∠ BAC = 150 °, then ∠ DAB =, ∠ DAE= Why
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