In RT triangle ABC, ∠ C = 90 °, ab = 2, radical 2, BC = radical 6, solve this right triangle
∠C=90°
AB is a hypotenuse
Pythagorean theorem
AC=√(AB²-BC²)=√(8-6)=√2
∵sinA=AC/AB=1/2
∴∠A=30°
∠B=90°-30°=60°
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