This is a problem of mathematical geometry. How to find the degree of ∠ a in triangle △ ABC AB = AC BC = BD ad = de = EB?

This is a problem of mathematical geometry. How to find the degree of ∠ a in triangle △ ABC AB = AC BC = BD ad = de = EB?

∵AB=AC,BC=BD,AD=DE=EB,
∴∠A=∠AED,∠ABC=∠C=∠BDC,∠EDB=∠EBD
Let a = x, because AED = EDB + EBD
Therefore, EDB = EBD = x / 2
∵∠BDC=∠A+∠ABD=x+x/2=3x/2
∴∠BDC=∠C=∠ABC=3x/2
∵∠A+∠ABC+∠C=180°
∴X+3X/2*2=180
We get x = 45 degrees
The degree of a is 45 degrees