As shown in the figure, CD is the height on the hypotenuse of RT △ ABC, e is the midpoint of AC, and the extended line of ED intersects CB at point F. prove BD * CF = CD * DF
∵ CD is the height of the hypotenuse of RT △ ABC
In RT △ ACD, e is the midpoint of AC
∴AE=CE=DE ∴∠A=∠ADE
And ∠ ade = ∠ BDF
∴∠BCD=∠BDF ∴△DBF∽△CDF
So BD / CD = DF / CF, so BD * CF = CD * DF
OK. If it is correct, please adopt it
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