It is known that in △ ABC, ∠ ACB = 90 ° AC = BC, the straight line Mn passes through point C, and ad ⊥ Mn is in D, be ⊥ Mn is in E

It is known that in △ ABC, ∠ ACB = 90 ° AC = BC, the straight line Mn passes through point C, and ad ⊥ Mn is in D, be ⊥ Mn is in E

This is the proof: 1) the following: ① \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\- CD, de = ad-be