If AC = 3cm, BC = 4cm, ab = 5cm, the distance from point d to the three sides is A.2.5cm B.2cm C.1.5cm D.1cm
The distance from the point on the bisector to both sides of the corner is equal, so let the distance from D to the three sides be X
Using the area method,
Δ ABC area = = = 1 / 2 * 3 * 4 = 6cm & # 178;
Δ ABC area = = △ abd area + △ ACD area + △ BCD area = 1 / 2 (3x + 4x + 5x) = 6xcm & # 178;
So 6x = 6,
x=1cm
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