In the regular triangular pyramid p-abc, e f is the midpoint of the side edges Pb and BC respectively, and AE ⊥ EF, PA = root 2 to calculate the volume
Make the midpoint D of AB, connect PD and CD, because PA = Pb, AC = BC, so ab ⊥ PD, ab ⊥ CD, then ab ⊥ plane PCD, get ab ⊥ PC from PC in plane PCD, because EF is the midpoint of Pb and BC, so EF / / PC and AE ⊥ EF, so AE ⊥ PC because AE and ab are two intersecting lines in plane PAB, so PC ⊥ plane PAB is PC ⊥
RELATED INFORMATIONS
- 1. As shown in the figure, BD is the bisector of ∠ ABC, de ⊥ AB is at point E, ab = 36cm, BC = 24cm, s △ ABC = 144cm, then the length of De is______ .
- 2. BD is the bisector of angle ABC, De is perpendicular to e, ab = 46, BC = 24, s △ ABC = 144
- 3. As shown in the figure, BD is the bisector of ∠ ABC, de ⊥ AB is at point E, ab = 36cm, BC = 24cm, s △ ABC = 144cm, then the length of De is______ .
- 4. In the triangle ABC, ∠ BCA = 90 ° and CD ⊥ AB is at point D. given AC = 3cm, BC = 4cm and ab = 5cm, what is the distance between point C and ab? RT The first answer is the best
- 5. If AC = 3cm, BC = 4cm, ab = 5cm, the distance from point d to the three sides is A.2.5cm B.2cm C.1.5cm D.1cm
- 6. It is known that in the right triangle ABC, C = 90 °, AC = 3cm, BC = 4cm, the midpoint of BC is O, Po ⊥ plane ABC, and Po = 5cm. Please tell me the detailed steps. I just learned solid geometry
- 7. In RT △ ABC, ∠ C = 90 °, ab = 5cm, AC = 4cm, BC = 3cm, the height on the edge of AB is
- 8. As shown in the figure, in the triangle ABC, D is the midpoint of BC, ad is perpendicular to BC at point D, De is perpendicular to ab at point E, de = 5cm, calculate the distance from point d to AC
- 9. As shown in the figure, in △ ABC, BD bisects ∠ ABC, and BD ⊥ AC intersects D, de ∥ BC intersects AB at E. AB = 5cm, AC = 2cm, then the perimeter of △ ade=______ cm.
- 10. In the triangle ABC, the angle c is equal to 90 degrees, the bisector angle ad of the angle cab intersects the point D, BC-AC = 2, BD = 5, and the distance between the point D and ab is calculated? This is the eighth grade problem, did not learn Pythagorean theorem
- 11. AB is the diameter of circle O, C is the point on circle O, PA is perpendicular to the plane of circle O, AE is perpendicular to Pb is perpendicular to e, AF is perpendicular to PC is perpendicular to F Let PA = root 3 and AC = 1 to find the distance between point a and PCB
- 12. It is known that PA is perpendicular to the plane of circle O, AB is the diameter of circle O, C is any point on circle O, and AE is perpendicular to PC through a Results: AE was perpendicular to the plane of PBC
- 13. A mathematical problem: PA is known to be perpendicular to the plane where the circle O lies, AB is the diameter of the circle O, C is any point on the circle O, make AE through a, and make PC perpendicular to E A mathematical problem: we know the plane where PA is perpendicular to circle O, AB is the diameter of circle O, C is any point on circle O, make AE perpendicular to PC through a, and prove that AE is perpendicular to plane PBC
- 14. In triangular pyramid p-abc, PA ⊥ plane ABC, AC ⊥ BC, through a as AE ⊥ PC, then PC to e, verification: AE ⊥ plane PBC
- 15. As shown in the figure: in △ ABC, ab = AC, take a little E on AC, extend Ba to F, make AF = AE, and connect Fe. At this time, there is a special position relationship between Fe and BC. Can you find out and explain it?
- 16. If the length of two right sides of a right triangle is 3 and 4, and the distance from a point in the triangle to each side is equal, then the distance is______ .
- 17. If the length of two right sides of a right triangle is 3 and 4, and the distance from a point in the triangle to each side is equal, then the distance is______ .
- 18. There are three points a, B and C on the sphere. It is known that ab = 3, AC = 4 and BC = 5. If the distance from the center of the sphere to the plane ABC is 6, the surface area of the sphere is 0
- 19. If it is known that the cross sections of three points a, B and C on the sphere and the distance between the center of the sphere are equal to half of the radius of the sphere, and ab = BC = CA = 2, then the area of the sphere is?
- 20. It is known that the distance between the cross sections of three points a, B, C and the center O of the sphere is equal to half of the radius of the sphere, and ab = BC = CA = 3