AB is the diameter of circle O, C is the point on circle O, PA is perpendicular to the plane of circle O, AE is perpendicular to Pb is perpendicular to e, AF is perpendicular to PC is perpendicular to F Let PA = root 3 and AC = 1 to find the distance between point a and PCB

E doesn't seem to work!
Even BC, ∵ BC is the diameter, ∵ BC ⊥ AC, PA ⊥ plane ABC, ∵ BC ⊥ PA,
The PAC of BC ⊥ plane, the BC of AF ⊥ plane, the PC of AF ⊥ plane and the PBC of AF ⊥ plane are required
AF=PA*AC/PC=√3/2.

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