A mathematical problem: PA is known to be perpendicular to the plane where the circle O lies, AB is the diameter of the circle O, C is any point on the circle O, make AE through a, and make PC perpendicular to E A mathematical problem: we know the plane where PA is perpendicular to circle O, AB is the diameter of circle O, C is any point on circle O, make AE perpendicular to PC through a, and prove that AE is perpendicular to plane PBC

Connect AC, because AB is the diameter of the circle, BC is perpendicular to AC (the triangle is a right triangle)
PA perpendicular to BC
So BC is perpendicular to PAC
So BC is perpendicular to Ae
Because AE is perpendicular to PC and PC BC is parallel to point C in the plane
So AE vertical plane PBC

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