BD is the bisector of angle ABC, De is perpendicular to e, ab = 46, BC = 24, s △ ABC = 144

The perpendicular of BC through D intersects BC with F
S△ABC=S△ABD+S△DBC=(DE*AB)/2+(DF*BC)/2=144
Because BD is the bisector of angle ABC, De is perpendicular to AB and DF is perpendicular to BC and F,
So de = DF
So (de * 46) / 2 + (de * 24) / 2 = 144
De = 144 / 35

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