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過D作BC的垂線交BC於F S△ABC=S△ABD+S△DBC=(DE*AB)/2+(DF*BC)/2=144 因為BD是角ABC的角平分線,DE垂直AB於E,DF垂直BC於F, 所以DE=DF 所以(DE*46)/2+(DE*24)/2=144 得DE=144/35
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