If it is known that the cross sections of three points a, B and C on the sphere and the distance between the center of the sphere are equal to half of the radius of the sphere, and ab = BC = CA = 2, then the area of the sphere is?

To find the area, that is, to find the radius r, mark the center O of the ball, and the center of the circle passing through ABC is O1. Because ABC is equilateral, the center of the triangle is also the center of the circle O1, so it is not difficult to find the radius r of the ball O1, find the radius r, and connect o1oa. Then it becomes a plane problem, a problem of finding the length of the side of a right triangle, that is, to find OA, which is r, Think for yourself, don't be lazy. Damn, I wasn't so smart at that time, and I did it all by myself. It's silly

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