As shown in the figure, CD is the height of the bottom edge ab of the isosceles triangle ABC. De is parallel to BC and intersects AC at point E. judge whether △ Dec is an isosceles triangle and explain the reason

As shown in the figure, CD is the height of the bottom edge ab of the isosceles triangle ABC. De is parallel to BC and intersects AC at point E. judge whether △ Dec is an isosceles triangle and explain the reason

Delta Dec is an isosceles triangle
Proof: because CD is the height of the base ab of the isosceles triangle ABC,
So D is the midpoint of ab
It's parallel to BC,
Then de = half of BC and E is the midpoint of AC, that is, EC = half of AC
And because AC = BC
So de = EC
So delta Dec is an isosceles triangle