In the triangle ABC, ab = AC, D is the midpoint of AB, De is perpendicular to AB, AC intersects with E, the circumference of EBC is known to be 10, and ac-bc = 1 The circumference of ABC

In the triangle ABC, ab = AC, D is the midpoint of AB, De is perpendicular to AB, AC intersects with E, the circumference of EBC is known to be 10, and ac-bc = 1 The circumference of ABC

In the triangle Abe, ED is perpendicular to AB, ad = dB, AE = EB is obtained from the combination of three lines, be + EC + BC = AE + EC + BC = AC + BC = 10 is obtained from the perimeter of the triangle EBC of 10. Then AC and BC are regarded as unknowns by ac-bc = 1, and AC = 5.5 and BC = 4.5 are obtained by solving the equation. Therefore, the perimeter of the triangle ABC is AC + BC + AB = 15.5