As shown in the figure, in △ ABC, EF is the median line of △ ABC, D is a point on the side of BC (not coincident with B and C), ad and EF intersect at point O to connect de and DF. To make quadrilateral AEDF a parallelogram, conditions need to be added______ (only add one condition, the answer is not unique)

Add: BD = CD. Reason: ∵ EF is the median line of △ ABC ∵ CF = AF, AE = 12ab. ∵ BD = CD, ∵ point D is the midpoint of BC, DF is the median line. ∥ DF ∥ AE therefore, in order to make quadrilateral AEDF parallelogram, according to a group of parallel and equal quadrilateral is parallelogram, we need to add the condition BD = CD. So the answer is BD = CD (the answer is not unique)

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