In the parallelogram ABCD, AE bisection ∠ DAB intersects DC with E, BF bisection ∠ ABC intersects DC with F, DC = 8cm, ad = 3cm, find the length of De, DF and FC RT
Because it's an angular bisector, so angle FBC + angle BFC + angle c = angle c + angle B, so BC = FC. The following are similar. The final conclusion is that
DF=5
CF=3
DE=3
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