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It is known that, as shown in the figure, in △ ABC, ∠ ABC = 66 ° and ∠ ACB = 54 ° be and CF are the heights of AC and AB on both sides, and they intersect at point h. calculate the degree of ∠ Abe and ∠ BHC
In ∵ △ ABC, ∵ ABC = 66 °, ∵ ACB = 54 °, ∵ a = 180 ° - ∵ ABC - ∵ ACB = 180 ° - 66 ° - 54 ° = 60 °, ∵ be ⊥ AC, ∵ AEB = 90 °, ∵ Abe = 90 ° - a = 90 ° - 60 ° = 30 °; similarly, ∵ CF ⊥ AB, ∵ BFC = 90 °, ∵ BHF = 90 ° - Abe = 90 ° - 30 ° = 60 °, ∵ BHC = 180 ° - BHF = 180 ° - 60 ° = 120 °
RELATED INFORMATIONS
- 1. As shown in the figure, in the triangle ABC, angle A: angle ABC: angle ACB = 4:5:6, BD and CE are the intersection points h of height, BD and Ce on AC and ab respectively, and the degree of angle BHC is calculated
- 2. As shown in the figure, in the triangle ABC, the known angle ABC is 66 degrees, the angle ACB is 54 degrees, be is the height of AC, h is the intersection of be and CF, and the angle Abe and angle ACF are calculated Degree of sum angle bec
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- 4. D is a point on the bisector of an outer angle of the triangle ABC, connecting dB and DC to prove AB + AC < DB + DC
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