As shown in the figure, in the triangle ABC, the known angle ABC is 66 degrees, the angle ACB is 54 degrees, be is the height of AC, h is the intersection of be and CF, and the angle Abe and angle ACF are calculated Degree of sum angle bec

First, the angle a = 60 °, be is high, so the angle BEA is 90 °, so the angle Abe = 90 ° - 60 ° = 30 ° CF is high, the angle AFC = 90 °, so the angle ACF = 30 ° and the angle BHC is the external angle of the angle ACF, so 30 ° + 90 ° = 120 ° is right. I just graduated from junior high school

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