As shown in the figure, in △ ABC, ad ⊥ BC is at point D, AE bisects ⊥ BAC intersects BC at e, ⊥ C = 70 ° and ⊥ B = 38 ° to find the degree of ⊥ DAE

As shown in the figure, in △ ABC, ad ⊥ BC is at point D, AE bisects ⊥ BAC intersects BC at e, ⊥ C = 70 ° and ⊥ B = 38 ° to find the degree of ⊥ DAE

It should be 16 degrees
In △ ABC, ∠ C = 70 ° and ∠ B = 38 °, so ∠ BAC = 72 °;
Because AE divides ∠ BAC equally, so ∠ BAE = ∠ CAE = (1 / 2) ∠ BAC = 36 °;
Because ad ⊥ BC, then ∠ CAD = 90 - ∠ C = 90-70 = 20 degree
So ∠ DAE = ∠ CAE - ∠ CAD = 36-20 = 16 °