As shown in the figure, in RT △ ABC, ∠ B = 90 °, a = 30 ° and AC = 3, bend BC toward Ba, so that point C falls on point C 'on Ba, and the crease is be, then the length of C' e is___ .
In RT △ ABC, ABC = 90 °, a = 30 °, C = 60 °, ∵ AC = 3, ∵ BC = 32, ab = 332 ∵ c'eb has ∵ CBE folding, ∵ BC = CB ', ∵ bc'e = ∠ C = 60 °, ∵ bc'e = ∠ a + ∠ AEC', ∵ 60 ° = 30 ° + ∠ AEC ', ∵ AEC' = 30 ° AC '= c'e ∵ c'e = AC' = ab-bc '= 332-32 = 3 (3-1) 2. So the answer is: 3 (3-1) 2
RELATED INFORMATIONS
- 1. It is known that, as shown in the figure, ad is the angular bisector of △ ABC, and EF bisectors ad vertically, intersecting AB and AC at e and f respectively
- 2. It is known that ad is the angular bisector of △ ABC, de ∥ AC intersects AB at point E, DF ∥ AB intersects AC at point F
- 3. It is known that ad is the angular bisector of △ ABC, de ∥ AC intersects AB at point E, DF ∥ AB intersects AC at point F
- 4. As shown in the figure, in △ ABC, ad is the height of BC, AE is divided equally into ∠ BAC, ∠ B = 75, ∠ C = 45, and ∠ Daewoo and ∠ AEC are calculated
- 5. In △ ABC, a-c = 90 ° AE is the bisector of BAC, and the degree of AEC is calculated
- 6. In △ ABC, ∠ BAC = 90 °, BD bisection ∠ ABC, AE ⊥ BC in E. verification: AF = ad
- 7. In △ ABC, ∠ BAC = 90 °, BD bisection ∠ ABC, AE ⊥ BC in E. verification: AF = ad
- 8. In triangle ABC, ad is high, be is middle line, angle CBE = 30 degrees, prove: ad = be
- 9. It is known that be is the middle line ad ⊥ BC in △ ABC, and it is shown that ad = be
- 10. In △ ABC, be is the middle line, ad ⊥ BC is in D, ∠ CBE = 30 °, please prove: ad = be The figure can be drawn according to the title. There are three sides of the triangle, one middle line and one high line. There are five sides in total
- 11. As shown in the figure, in △ ABC, point P moves from point B along the Ba edge to point a at a speed of 1cm / s, and point Q also moves from point B along the BC edge to point C at a speed of 2cm / s. After a few seconds, the area of △ PBQ is 36cm2?
- 12. As shown in the figure, in the RT triangle ABC, ∠ C = 90, AC = 6cm, BC = 8cm, points E and f start from two points a and B at the same time and move to points c and B along the direction of AC and Ba respectively The velocity of point E is 2cm / s, and that of point F is 1cm / s. if one of the points reaches the position, both points stop moving (1) Q. after a few seconds, the area of the triangle AEF is 16 / 5 (2) After a few seconds, EF bisects the perimeter of the RT triangle (3) Is there a line EF that bisects the perimeter and area of rtabc at the same time? If so, calculate the length of AE. If not, explain the reason
- 13. As shown in the figure, in the RT triangle ABC & nbsp;, the angle c = 90 °, AC = 3, BC = 4, a straight line & nbsp; l intersects with the edge BC and Ba and points & nbsp; E and f respectively, and the area of the divided triangle ABC & nbsp; is two equal parts, then the minimum length of the segment EF & nbsp; is______ .
- 14. As shown in the figure, in RT △ ABC, ∠ ABC is a right angle, ab = 3, BC = 4, P is the moving point on the edge of BC, let BP = x, if we can find a point Q on the edge of AC, so that ∠ BQP = 90 °, then the value range of X is______ .
- 15. 1. As shown in the figure: in the RT triangle ABC, the angle ABC = 90, Ba = BC. Point D is the midpoint of AB, CD, through point B as BC, vertical CD 1. As shown in the figure: in the RT triangle ABC, the angle ABC = 90, Ba = BC. Point D is the midpoint of AB, CD, passing through point B, BC is the vertical CD, intersecting CD and Ca at points E and f respectively. The straight line passing through point a and perpendicular to AB intersects at point G, connecting DF. The following four conclusions are given: (1) Ag ratio AB = FG ratio FB; (2) point F is the midpoint of Ge; (3) AF = 3 molecular root 2Ab; (4) s triangle ABC = 5S triangle BDF, The correct conclusion is as follows There are specific solutions
- 16. As shown in the figure, in △ ABC, ad ⊥ BC is at point D, AE bisects ⊥ BAC intersects BC at e, ⊥ C = 70 ° and ⊥ B = 38 ° to find the degree of ⊥ DAE
- 17. It is known as follows: as shown in the figure, in △ ABC, ad is the height on the edge of BC, AE is the bisector of ∠ BAC, ∠ B = 50 °, DAE = 10 °, (1) find the degree of ∠ BAE; (2) find the degree of ∠ C
- 18. In △ ABC, be bisects ∠ ABC, ad is the height on BC, and ∠ ABC = 60 ° and ∠ BEC = 75 ° to calculate the degree of ∠ DAC
- 19. As shown in the figure, in △ ABC, ∠ C = 90 °, the vertical bisector of AB intersects at point D, AB intersects at point E, the degree ratio of ∠ DAE and ∠ DAC is 2:1, and the degree of ∠ B is calculated
- 20. As shown in the figure, in △ ABC, ∠ C = 90 °, the vertical bisector of AB intersects at point D, AB intersects at point E, the degree ratio of ∠ DAE and ∠ DAC is 2:1, and the degree of ∠ B is calculated