It is known that, as shown in the figure, ad is the angular bisector of △ ABC, and EF bisectors ad vertically, intersecting AB and AC at e and f respectively
Ad is the angular bisector of △ ABC
So the two angles are equal
EF vertical split ad
So the two adjacent angles are equal, and the tangent is 90 degrees
In addition, two triangles share an edge, and the edge triangles are congruent
As above, we can prove that the four sides are equal, so the diamond appears
RELATED INFORMATIONS
- 1. It is known that ad is the angular bisector of △ ABC, de ∥ AC intersects AB at point E, DF ∥ AB intersects AC at point F
- 2. It is known that ad is the angular bisector of △ ABC, de ∥ AC intersects AB at point E, DF ∥ AB intersects AC at point F
- 3. As shown in the figure, in △ ABC, ad is the height of BC, AE is divided equally into ∠ BAC, ∠ B = 75, ∠ C = 45, and ∠ Daewoo and ∠ AEC are calculated
- 4. In △ ABC, a-c = 90 ° AE is the bisector of BAC, and the degree of AEC is calculated
- 5. In △ ABC, ∠ BAC = 90 °, BD bisection ∠ ABC, AE ⊥ BC in E. verification: AF = ad
- 6. In △ ABC, ∠ BAC = 90 °, BD bisection ∠ ABC, AE ⊥ BC in E. verification: AF = ad
- 7. In triangle ABC, ad is high, be is middle line, angle CBE = 30 degrees, prove: ad = be
- 8. It is known that be is the middle line ad ⊥ BC in △ ABC, and it is shown that ad = be
- 9. In △ ABC, be is the middle line, ad ⊥ BC is in D, ∠ CBE = 30 °, please prove: ad = be The figure can be drawn according to the title. There are three sides of the triangle, one middle line and one high line. There are five sides in total
- 10. As shown in the figure, points a, B, D and E are on ⊙ o, and the extension lines of strings AE and BD intersect at point C. If AB is the diameter of ⊙ o, D is the midpoint of BC. Try to judge the size relationship between AB and AC, and give the proof Under the above conditions, what other conditions do △ ABC need to satisfy, and point e must be the midpoint of AC?
- 11. As shown in the figure, in RT △ ABC, ∠ B = 90 °, a = 30 ° and AC = 3, bend BC toward Ba, so that point C falls on point C 'on Ba, and the crease is be, then the length of C' e is___ .
- 12. As shown in the figure, in △ ABC, point P moves from point B along the Ba edge to point a at a speed of 1cm / s, and point Q also moves from point B along the BC edge to point C at a speed of 2cm / s. After a few seconds, the area of △ PBQ is 36cm2?
- 13. As shown in the figure, in the RT triangle ABC, ∠ C = 90, AC = 6cm, BC = 8cm, points E and f start from two points a and B at the same time and move to points c and B along the direction of AC and Ba respectively The velocity of point E is 2cm / s, and that of point F is 1cm / s. if one of the points reaches the position, both points stop moving (1) Q. after a few seconds, the area of the triangle AEF is 16 / 5 (2) After a few seconds, EF bisects the perimeter of the RT triangle (3) Is there a line EF that bisects the perimeter and area of rtabc at the same time? If so, calculate the length of AE. If not, explain the reason
- 14. As shown in the figure, in the RT triangle ABC & nbsp;, the angle c = 90 °, AC = 3, BC = 4, a straight line & nbsp; l intersects with the edge BC and Ba and points & nbsp; E and f respectively, and the area of the divided triangle ABC & nbsp; is two equal parts, then the minimum length of the segment EF & nbsp; is______ .
- 15. As shown in the figure, in RT △ ABC, ∠ ABC is a right angle, ab = 3, BC = 4, P is the moving point on the edge of BC, let BP = x, if we can find a point Q on the edge of AC, so that ∠ BQP = 90 °, then the value range of X is______ .
- 16. 1. As shown in the figure: in the RT triangle ABC, the angle ABC = 90, Ba = BC. Point D is the midpoint of AB, CD, through point B as BC, vertical CD 1. As shown in the figure: in the RT triangle ABC, the angle ABC = 90, Ba = BC. Point D is the midpoint of AB, CD, passing through point B, BC is the vertical CD, intersecting CD and Ca at points E and f respectively. The straight line passing through point a and perpendicular to AB intersects at point G, connecting DF. The following four conclusions are given: (1) Ag ratio AB = FG ratio FB; (2) point F is the midpoint of Ge; (3) AF = 3 molecular root 2Ab; (4) s triangle ABC = 5S triangle BDF, The correct conclusion is as follows There are specific solutions
- 17. As shown in the figure, in △ ABC, ad ⊥ BC is at point D, AE bisects ⊥ BAC intersects BC at e, ⊥ C = 70 ° and ⊥ B = 38 ° to find the degree of ⊥ DAE
- 18. It is known as follows: as shown in the figure, in △ ABC, ad is the height on the edge of BC, AE is the bisector of ∠ BAC, ∠ B = 50 °, DAE = 10 °, (1) find the degree of ∠ BAE; (2) find the degree of ∠ C
- 19. In △ ABC, be bisects ∠ ABC, ad is the height on BC, and ∠ ABC = 60 ° and ∠ BEC = 75 ° to calculate the degree of ∠ DAC
- 20. As shown in the figure, in △ ABC, ∠ C = 90 °, the vertical bisector of AB intersects at point D, AB intersects at point E, the degree ratio of ∠ DAE and ∠ DAC is 2:1, and the degree of ∠ B is calculated