As shown in the figure, △ ABC, ab = AC, ∠ BAC = 110 °, ad is the middle line on the side of BC, and BD = be, then ∠ AED degree is______ ．

In ∵ ABC, ab = AC, ∵ BAC = 110 °, ∵ B = ∵ C = 12 × (180 ° - ∵ BAC) = 12 × (180 ° - 110 °) = 35 °, ∵ BD = be, ∵ bed = ∵ BDE = 12 × (180 ° - ∵ b) = 12 × (180 ° - 35 °) = 72.5 °, ∵ AED = 180 ° - 72.5 ° = 107.5 °. So the answer is: 107.5 °

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