Triangle ABC is an equilateral triangle, D is the midpoint of side AB, de and BC are perpendicular, and the area of triangle BDE is 5 square centimeters. Find the area of triangle ABC

Let the intersection of AF and BC be f, then the bottom and height of △ ABF are twice that of △ BDE, and the area of △ ABC is 4 times that of △ BDE, so the area of △ ABC is 8 times that of △ BDE, and the result is 40

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1. Triangle ABC and triangle BDE are equilateral triangles. This paper proves that: (1) triangle ABC is equal to triangle CBD (2) AE = De Please, hurry up
2. As shown in the figure, in △ ABC, CF ⊥ AB is in F, be ⊥ AC is in E, M is the midpoint of BC, EF = 5, BC = 8, then the perimeter of △ EFM is______ ．
3. As shown in the figure, in △ ABC, CF ⊥ AB is in F, be ⊥ AC is in E, M is the midpoint of BC, EF = 5, BC = 8, then the perimeter of △ EFM is______ ．
4. In triangle ABC, CF is perpendicular to AB and be is perpendicular to AC and E. m is the midpoint of BC, BF = 5 and BC = 8. Can you determine the perimeter of triangle EFM?
5. As shown in the figure, in △ ABC, ab = AC, D, e and F are on three sides respectively, and be = CD, BD = CF, G is the midpoint of EF
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7. Finding AF / ad = ad / AB in triangle ABC by de / / BC EF / / CD
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15. It is known that in △ ABC, D is any point on the edge of ab Please write down the steps clearly
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