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In the triangle ABC, BD is perpendicular to AC at point D, CE is perpendicular to ab at point E, BD and CE intersect at point h, ad = DH = 1, CD = 5, find the area of triangle ABC. If you can't send the graph, please draw it by yourself. The top vertex is a, and the bottom is left B and right C
∠ADB=∠CDH=90
∠ABD=90-∠A
Therefore, abd = ace
Triangle abd is similar to triangle CDH
BD：AD=CD：DH
AD=DH=1 CD=5
So BD = 5
Area of triangle ABC = 1 / 2Ac * BD = 1 / 2 (1 + 5) * 5 = 15
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