As shown in the figure, ⊿ ABC is an isosceles triangle, ∠ ABC = 90? Therefore, B = 10, D is a point outside ⊿ ABC, connecting AD.BD If point h, AC ⊥ abd is an equilateral triangle, find the length de: (2) if BD = AB, and DH BH = 3 / 4

Solutions: (1) the ∵ abd is an equilateral triangle, ab = 10, ∵ ADB = 60? Shang = ∵ DH ⊥ AB, ab = 10, ∵ ah = 12ab = 5, ∵ DH = ad2-ah2 = 102 - 52 = 53, ∵ ABC is an isosceles triangle,

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