A (0,0), B (- 3, - 4) C (4, - 2), draw these points (done) in the plane rectangular coordinate system, find the area of △ ABC, the first question has been done

A (0,0), B (- 3, - 4) C (4, - 2), draw these points (done) in the plane rectangular coordinate system, find the area of △ ABC, the first question has been done

AB=√[(-3)²+(-4)²]=5
The equation of line AB is 4x-3y = 0
The distance from point C (4, - 2) to line AB is
|16+6|/√(3²+4²)=22/5
therefore
The area of triangle ABC is
S=(1/2)*5*(22/5)=11